\(\frac{5x+2y}{3}\text{ equals }\frac{y-4x}{5}\text{ then:}25x+10y=3y-12x\text{ therefore:}37x=-7x\)
\(\Rightarrow\frac{37}{-7}x=y\text{ therefore:}x+3y=\frac{104}{-7}x=-8\Rightarrow x=\frac{13}{7}\Rightarrow y=\frac{13.37}{-49}=...\text{ then}\)
\(\text{COMPUTE IT YOURSELF}\)