\(K+H_2O\rightarrow KOH+\dfrac{1}{2}H_2\)
\(n_K=2n_{H_2}=0,2\left(mol\right)\Rightarrow m_K=7,8\left(g\right)\)
=> \(m_{K_2O}=17,2-7,8=9,4\Rightarrow n_{K_2O}=0,1\left(mol\right)\)
\(K_2O+H_2O\rightarrow2KOH\)
\(\Sigma n_{KOH}=0,2+0,1.2=0,4\left(mol\right)\)
\(m_{ddsaupu}=17,2+600-0,1.2=617\left(g\right)\)
=> \(C\%_{KOH}=\dfrac{0,4.56}{712}.100=3,15\%\)