Question

Help Me!!

a)(x-5)²²+(y+7)¹²=0

 

 

Answer 1

Vì (x-5)²²\(\ge\)0
    \(\left(y+7\right)^{12}\ge0\)
Mà \(\left(x-5\right)^{22}+\left(y+7\right)^{12}=0\)
Nên \(\hept{\begin{cases}\left(x-5\right)^{22}=0\\\left(y+7\right)^{12}=0\end{cases}}\Rightarrow\hept{\begin{cases}x-5=0\\y+7=0\end{cases}}\Rightarrow\hept{\begin{cases}x=5\\y=-7\end{cases}}\)

Answer 2

Vì (x - 5)²² ≥ 0 ; (y + 7)¹² ≥ 0

=> (x - 5)²² + (y + 7)¹² ≥ 0

Dấu "=" xảy ra khi (x - 5)²² = 0 ; (y + 7)¹² = 0

=> x = 5 ; y = - 7

Vậy  x = 5 ; y = - 7