Các câu hỏi tương tự
14 tháng 6 2020 lúc 20:14
Giải phương trình sau:
\(\frac{2}{\left(1-3u\right)\left(3u+1\right)}=\frac{1}{9u^2-6u+1}-\frac{3}{\left(3u+1\right)^2}\)
Chứng minh: \(\frac{2}{x^2-1}+\frac{4}{x^2-4}+...+\frac{20}{x^2-100}=\frac{11}{\left(x-10\right)\left(x+1\right)}+\frac{11}{\left(x-9\right)\left(x+2\right)}+...+\frac{11}{\left(x-1\right)\left(x+10\right)}\)
Tìm điều kiện xác định rồi giải các phương trình sau:a) frac{x-2}{2+x}-frac{3}{x-2}frac{2left(x-11right)}{x^2-4}b) frac{3}{4left(x-5right)}+frac{15}{50-2x^2}frac{-7}{6left(x+5right)}c) frac{8x^2}{3left(1-4x^2right)}frac{2x}{6x-3}-frac{1+8x}{4+8x}d) frac{13}{left(x-3right)left(2x+7right)}+frac{1}{2x+7}frac{6}{x^2-9}Help me!
Đọc tiếp
Tìm điều kiện xác định rồi giải các phương trình sau:
a) \(\frac{x-2}{2+x}-\frac{3}{x-2}=\frac{2\left(x-11\right)}{x^2-4}\)
b) \(\frac{3}{4\left(x-5\right)}+\frac{15}{50-2x^2}=\frac{-7}{6\left(x+5\right)}\)
c) \(\frac{8x^2}{3\left(1-4x^2\right)}=\frac{2x}{6x-3}-\frac{1+8x}{4+8x}\)
d) \(\frac{13}{\left(x-3\right)\left(2x+7\right)}+\frac{1}{2x+7}=\frac{6}{x^2-9}\)
Help me!
help me! (ngu toàn tập)a)frac{3}{left(1.2right)^2}+frac{5}{left(2.3right)^2}+...+frac{2n+1}{left[nleft(n+1right)right]^2}b)left(1-frac{1}{2^2}right)left(1-frac{1}{3^2}right)left(1-frac{1}{4^2}right)....left(1-frac{1}{n^2}right)c)frac{150}{5.8}+frac{150}{8.11}+frac{150}{11.14}+...+frac{150}{47.50}d)frac{1}{1.2.3}+frac{1}{2.3.4}+frac{1}{3.4.5}+...+frac{1}{left(n-1right)nleft(n+1right)}
Đọc tiếp
help me! (ngu toàn tập)
a)\(\frac{3}{\left(1.2\right)^2}+\frac{5}{\left(2.3\right)^2}+...+\frac{2n+1}{\left[n\left(n+1\right)\right]^2}\)
b)\(\left(1-\frac{1}{2^2}\right)\left(1-\frac{1}{3^2}\right)\left(1-\frac{1}{4^2}\right)....\left(1-\frac{1}{n^2}\right)\)
c)\(\frac{150}{5.8}+\frac{150}{8.11}+\frac{150}{11.14}+...+\frac{150}{47.50}\)
d)\(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{\left(n-1\right)n\left(n+1\right)}\)
GPT :a, left(1+frac{1}{2}+frac{1}{3}+...+frac{1}{2011}+frac{1}{2012}..right).503x1+frac{2014}{2}+frac{2015}{3}+...+frac{4023}{2011}+frac{4024}{2012}b, left(frac{0,6+frac{3}{7}-frac{2}{11}}{1+frac{5}{7}-frac{5}{11}}+frac{frac{2}{3}-1,5+frac{2}{9}}{frac{5}{3}-3,75+frac{5}{9}}right)+93xleft(frac{3737}{4545}-frac{954954}{975975}right).left(frac{1}{2}-frac{1}{3}-frac{1}{6}right)-7.left(x-3right)
Đọc tiếp
GPT :
a, \(\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2011}+\frac{1}{2012}..\right).503x=1+\frac{2014}{2}+\frac{2015}{3}+...+\frac{4023}{2011}+\frac{4024}{2012}\)
b, \(\left(\frac{0,6+\frac{3}{7}-\frac{2}{11}}{1+\frac{5}{7}-\frac{5}{11}}+\frac{\frac{2}{3}-1,5+\frac{2}{9}}{\frac{5}{3}-3,75+\frac{5}{9}}\right)+93x=\left(\frac{3737}{4545}-\frac{954954}{975975}\right).\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)-7.\left(x-3\right)\)
1. Gỉai các phương trình sau
\(a,\left(x-3\right)^3-2\left(x-1\right)=x\left(x-2\right)^2-5x^2\)
\(b,\frac{\left(x+1\right)^2}{3}+\frac{\left(x+2\right)\left(x-3\right)}{2}=\frac{\left(5x-1\right)\left(x-4\right)}{6}+\frac{28}{3}\)
\(c,\frac{x+1}{94}+\frac{x+2}{93}+\frac{x+3}{92}=\frac{x+4}{91}+\frac{x+5}{90}+\frac{x+6}{89}\)
HELP ME!
23 tháng 8 2016 lúc 10:43
Tính : \(\frac{\left(1^4+\frac{1}{4}\right)\left(3^4+\frac{1}{4}\right)\left(5^4+\frac{1}{4}\right)\left(7^4+\frac{1}{4}\right)\left(9^4+\frac{1}{4}\right)\left(11^4+\frac{1}{4}\right)}{\left(2^4+\frac{1}{4}\right)\left(4^4+\frac{1}{4}\right)\left(6^4+\frac{1}{4}\right)\left(8^4+\frac{1}{4}\right)\left(10^4+\frac{1}{4}\right)\left(12^4+\frac{1}{4}\right)}\)
Giải các phương trình
a. \(\frac{1-x}{x+1}+3=\frac{2x+3}{x+1}\)
b. \(\frac{\left(x+2\right)^2}{2x-3}-1=\frac{x^2+10}{2x-3}\)
c. \(\left(2-3x\right)\left(x+11\right)=\left(3x-2\right)\left(2-5x\right)\)
d.\(\left(2x^2+1\right)\left(4x-3\right)=\left(2x^2+1\right)\left(x-12\right)\)
GPT:
\(\left(1\right)\left(2-3x\right)\left(x+11\right)=\left(3x-2\right)\left(2-5x\right)\)
\(\left(2\right)\frac{x-3}{x+3}-\frac{x+3}{x-3}=-\frac{5}{x^2-9}\)