B=3^10.11+3^10.5/3^9.2^4
= 3^10( 11+5)/3^9.16
= 3^10.16/3^9.16
= 3^10/3^9
= 3
Vậy B = 3 (1)
C = 2^10.13+2^10.65/2^8.104
= 2^10(13+65)/2^8.2^2.26
= 2^10.78/2^10.26
= 78/26
= 3
Vậy C = 3 (2)
Từ (1) v (2) suy ra B=C
Rút gọn biểu thức:
\(\frac{2^{12}\cdot13+2^{12}\cdot65}{2^{10}\cdot104}+\frac{3^{10}\cdot11+3^{10}\cdot5}{3^9\cdot2^4}\)
Bài 22 : a, Cho A = 4 + 22 + 23 + 24 + ... + 220
Hỏi A có chia hết cho 128 không ?
b, Tính giá trị biểu thức
\(\frac{2^{12}\cdot13+2^{12}\cdot65}{2^{10}\cdot104}+\frac{3^{10}\cdot11+3^{10}\cdot5}{3^9\cdot2^4}\)
b\(^{\frac{2^{10\cdot13+2^{10}\cdot65}}{2^8\cdot104}}\)
c) \(\frac{5\cdot4^{15}-99-4\cdot3^{20}\cdot89}{5\cdot29\cdot6^{19}\cdot7\cdot2^{29}\cdot27^6}\)
b\(^{\frac{2^{10\cdot13+2^{10}\cdot65}}{2^8\cdot104}}\)
c) \(\frac{5\cdot4^{15}-99-4\cdot3^{20}\cdot89}{5\cdot29\cdot6^{19}\cdot7\cdot2^{29}\cdot27^6}\)
Tính gíá trị biểu thức :
A= \(\frac{3^{10}\cdot11+\left(3^2\right)^5:5}{24\cdot27}\)
B= \(\frac{2^{10}\cdot13+2^{10}\cdot65}{28\cdot104}\)
AI NHANH MK K CHO
a,\(A=\frac{3^{10}\cdot11+\left(3^2\right)^5:5}{27\cdot24}\)
b, \(B=\frac{2^{10}+13+2^{10}\cdot65}{28\cdot104}\)
\(\frac{2^{13}+2^5}{2^{10}+2^2}\)
\(\frac{2^{10}\cdot13+2^{10}\cdot65}{2^8\cdot104}\)
\(\frac{2^{13}+2^5}{2^{10}+2^2}=\)
\(\frac{2^{10}\cdot13+2^{10}\cdot65}{2^8\cdot104}=\)
CẢ CÁCH LÀM NỮA NHÉ<-_->
a, Rút gọn phân số :
\(\frac{\left(-2\right)^3\cdot3^3\cdot5^3\cdot7\cdot8}{3\cdot5^3\cdot2^4\cdot42}\)
b, so sánh không qua quy đồng :
A=\(\frac{-7}{10^{2005}}\)+\(\frac{-15}{10^{2006}}\)
B=\(\frac{-15}{10^{2005}}\)+\(\frac{-7}{10^{2006}}\)
