Question

Giúp tui vs đêm r làm phiền mng quá

Answer 1

Bài 1:

\(a,3x^2-6x+9x^3=3x\left(x-2+3x^2\right)=3x\left[\left(3x^2+3x\right)-\left(2x+2\right)\right]=3x\left(x+1\right)\left(3x-2\right)\\ b,2x+2y-x^2-xy=2\left(x+y\right)-x\left(x+y\right)=\left(x+y\right)\left(2-x\right)\\ c,x^2-2x-4y^2-4y=\left(x-2y\right)\left(x+2y\right)-2\left(x+2y\right)=\left(x+2y\right)\left(x-2y-2\right)\)

\(d,x^2y-x^3-9y+9x=x^2\left(y-x\right)-9\left(y-x\right)=\left(y-x\right)\left(x^2-9\right)=\left(y-x\right)\left(x-3\right)\left(x+3\right)\\ e,x^2-25+y^2+2xy=\left(x+y\right)^2-5^2=\left(x+y-5\right)\left(x+y+5\right)\\ f,\left(x^2+1\right)^2-4x^2=\left(x^2-2x+1\right)\left(x^2+2x+1\right)=\left(x-1\right)^2\left(x+1\right)^2\)

\(g,x^2\left(x-1\right)+16\left(1-x\right)=\left(x-1\right)\left(x^2-16\right)=\left(x-1\right)\left(x-4\right)\left(x+4\right)\\ h,5x\left(x-2y\right)+2\left(2y-x\right)^2=5x\left(x-2y\right)+2\left(x-2y\right)^2=\left(x-2y\right)\left[5x+2\left(x-2y\right)\right]=\left(x-2y\right)\left(5x+2x-4y\right)=\left(x-2y\right)\left(7x-4y\right)\)

Answer 2

a: \(=3x\left(3x^2+x-2\right)\)

\(=3x\left(3x^2+3x-2x-2\right)\)

=3x(x+1)(3x-2)