a, \(=\left(x-8\right)\left(x+2\right)\)
b, \(=x\left(x^2+x-6\right)=x\left(x+3\right)\left(x-2\right)\)
c, \(=-5x^2+15x+x-3=5x\left(3-x\right)-\left(3-x\right)=\left(3-x\right)\left(5x-1\right)\)
d, \(=x^4+6x^2+9-x^2=\left(x^2+3\right)^2-x^2=\left(x^2+3-x\right)\left(x^2+3+x\right)\)
\(e,=\left(x^2+3x-1\right)^2-4-5=\left(x^2+3x-1\right)^2-9\\ =\left(x^2+3x-4\right)\left(x^2+3x+2\right)=\left(x+4\right)\left(x-1\right)\left(x+1\right)\left(x+2\right)\\ f,=\left(x^2+10x+16\right)\left(x^2+10x+24\right)+7\\ =\left(x^2+10x+20\right)^2-16+7=\left(x^2+10x+20\right)^2-9\\ =\left(x^2+10x+17\right)\left(x^2+10x+23\right)\\ g,=\left(x^2+9\right)^2+8x\left(x^2+9\right)+16x^2-4x^2\\ =\left(x^2+4x+9\right)^2-4x^2=\left(x^2+6x+9\right)\left(x^2+2x+9\right)\\ =\left(x+3\right)^2\left(x^2+2x+9\right)\\ h,=\left(9x^2-12x+4\right)\left(36x^2-48x+15\right)-5\left(1\right)\\ \text{Đặt }9x^2-12x=a\\ \left(1\right)=\left(a+4\right)\left(4a+15\right)-5=4a^2+31a+55=\left(4a+11\right)\left(a+5\right)\\ =\left(36x^2-48x+11\right)\left(9x^2-12x+5\right)\)
giúp mik vs 
