Question

Giúp vs mai mik nộp rồi

Answer 1

a: Ta có: \(2x-3=0\)

\(\Leftrightarrow2x=3\)

hay \(x=\dfrac{3}{2}\)

b: Ta có: \(\left(2x+7\right)\left(x-3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{7}{2}\\x=3\end{matrix}\right.\)

c: Ta có: \(2x+7=-3x+32\)

\(\Leftrightarrow5x=25\)

hay x=5

d: Ta có: \(\left(3x-2\right)\left(4x+5\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=-\dfrac{5}{4}\end{matrix}\right.\)

e: Ta có: \(3x-5=x+7\)

\(\Leftrightarrow2x=12\)

hay x=6

Answer 2

f)ĐK:x≠2,x≠-1

Ta có:\(\dfrac{3}{x-2}=\dfrac{2}{x+1}\) 

    \(\Rightarrow3\left(x+1\right)=2\left(x-2\right)\)

   \(\Leftrightarrow3x+3=2x-4\)

   \(\Leftrightarrow x=-7\)