Question

Giúp tớ với ạ 

\(\frac{2\left(\sqrt{2}+\sqrt{6}\right)}{3\sqrt{2+\sqrt{3}}}\)

Answer 1

\(\frac{2\sqrt{2}\left(1+\sqrt{3}\right)}{\frac{3\left(1+\sqrt{3}\right)}{\sqrt{2}}}=\frac{2\sqrt{2}\sqrt{2}\left(1+\sqrt{3}\right)}{3\left(1+\sqrt{3}\right)}=\frac{4}{3}\)

Answer 2

\(\frac{2\sqrt{2}\left(1+\sqrt{3}\right)}{3\sqrt{\frac{4+2\sqrt{3}}{2}}}=\frac{2\sqrt{2}\left(1+\sqrt{3}\right)}{3\sqrt{\frac{3+2\sqrt{3}+1}{2}}}=\frac{2\sqrt{2}\left(1+\sqrt{3}\right)}{3\sqrt{\frac{\left(1+3\right)^2}{2}}}\)

Còn lại bạn giải tiếp đc chứ :D 

Answer 3

Không ạ =)))