Question

giup mk vs :\(\frac{3}{2^2}\times\frac{8}{3^2}\times\frac{15}{4^2}\times\frac{24}{5^2}...\frac{624}{25^2}\)

Answer 1

\(\frac{3}{2^2}\times\frac{8}{3^2}\times\frac{15}{4^2}\times\frac{24}{5^2}\times...\times\frac{624}{25^2}\)

\(=\frac{1.3}{2.2}\times\frac{2.4}{3.3}\times\frac{3.5}{4.4}\times...\times\frac{24.26}{25.25}\)

\(=\frac{1\times2\times3\times...\times24}{2\times3\times4\times...\times25}\times\frac{3\times4\times5\times...\times26}{2\times3\times4\times...\times25}\)

\(=\frac{1}{25}\times13\)

 \(=\frac{13}{25}\)

Answer 2

No, Thank!