(1/32)^100 = ((1/2)^5)^100 = (1/2)^500
(1/16)^120 = ((1/2)^4)^120 = (1/2)^480
=> (1/32)^100 > (1/16)^120
(1/32)^100=0
(1/16)^120=0
nen (1/32)^100=(1/16)^100
k cho minh nha
Ta có :(1/32)100=1.1/(2.16)100=1/2100.1/16100
(1/16)120=1/16120
Lại có :1/2100=1/2(25.4)=1/1625
Suy ra (1/32)100=1/16100.1/1625=1/16125
Do đó 1/16125<1/16100(Vì 16125>16100)
Hay (1/32)100<(1/16)120
ta có(1/32)^100 =(1/2^5)^100=1/2^500
(1/16)^120=(1/2^4)^120=1/2^480
mà 1/2^500<1/2^480
suy ra(1/32)^100<(1/16)^120
Ta có : \(\left(\frac{1}{32}\right)^{100}=\left(\frac{1}{2}\right)^{5.100}=\frac{1}{2}^{500}\)
\(\left(\frac{1}{16}\right)^{120}=\left(\frac{1}{2}\right)^{4.120}=\left(\frac{1}{2}\right)^{480}\)
Vì \(480<500\)
nên \(\left(\frac{1}{2}\right)^{480}>\left(\frac{1}{2}\right)^{500}\)
hay \(\left(\frac{1}{16}\right)^{120}>\left(\frac{1}{32}\right)^{100}\)
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