Question

Giúp mk với nha ,plz!!! Mk tick cho !!!! <3

Tính giá trị biểu thức 

E=\(\frac{4^6.9^5+6^9.120}{-8^4.3^{12}-6^{11}}\)

F=\(\frac{6^3+3.6^2+3^3}{-13}\)

 

Answer 1

E = \(\frac{\left(2^2\right)^6.\left(3^2\right) ^5+\left(2.3\right)^9.2^3.3.5}{-\left(2^3\right)^4.3^{12}-\left(2.3\right)^{11}}\)

E  =  \(\frac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{-2^{12}.3^{12}-2^{11}.3^{11}}\)

E = \(\frac{2^{12}.3^{10}+2^{13}.3^{10}.5}{-2^{11}.3^{11}.\left(2.3+1\right)}\)

E = \(\frac{2^{12}.3^{10}.\left(1+5\right)}{-2^{11}.3^{11}.7}\)

E = \(\frac{2^{12}.3^{10}.6}{-2^{11}.3^{11}.7}\)

E=\(\frac{-2^{11}.\left(-2\right).3^{10}.6}{-2^{11}.3^{10}.3.7}\)

E = \(\frac{-2.6}{3.7}=-\frac{4}{7}\)

Vậy E = -4/7 

Ý F bn lm tương tự nha 

Answer 2

thank bn nha