a, \(\dfrac{7}{8}+x=\dfrac{3}{5}\Leftrightarrow x=\dfrac{3}{5}-\dfrac{7}{8}=-\dfrac{11}{40}\)
b, \(2x-1=\dfrac{1}{3}:\left(-\dfrac{4}{27}\right)=\dfrac{1}{3}.\dfrac{-27}{4}=-\dfrac{9}{4}\)
c, \(\dfrac{17}{2}-\left(x-\dfrac{3}{4}\right)=-\dfrac{7}{4}\Leftrightarrow x-\dfrac{3}{4}=\dfrac{41}{4}\Leftrightarrow x=\dfrac{44}{4}=11\)
d, TH1 : 3x+2=0 ; TH2 -2/5x-7=0
<=> x = -2/3 hoặc x = 7:(-2/5) = -35/2
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