\(5x\left(2x-\frac{1}{2}\right)+2\left(2x-\frac{1}{2}\right)=0\)
<=>\(\left(2x-\frac{1}{2}\right)\left(5x+2\right)=0\)
<=>\(\orbr{\begin{cases}2x-\frac{1}{2}=0\\5x+2=0\end{cases}}\)
<=>\(\orbr{\begin{cases}x=\frac{1}{4}\\x=\frac{-2}{5}\end{cases}}\)
Vậy x=1/4 hoặc -2/5