Question

Giúp mình phân tích với ạ :

    x^2+4x-192

 

Answer 1

\(x^2+4x-192\)

\(=\left(x^2-12x\right)+\left(16x-192\right)\)

\(=x\left(x-12\right)+16\left(x-12\right)\)

\(=\left(x+16\right)\left(x-12\right)\)

Answer 2

\(x^2\)+4x−192

=(\(x^2\)−12x)+(16x−192)

=x(x−12)+16(x−12)

=(x+16)(x−12)

Answer 3

\(x^2+4x-192\)

\(\left(x^2-12x\right)+\left(16x-192\right)\)

\(=x\left(x-12\right)+16\left(x-12\right)\)

\(=\left(x+16\right)\left(x-12\right)\)