\(a,n_C=\dfrac{4}{12}=0,33(mol)\\ n_{H_2O}=\dfrac{3,6}{18}=0,2(mol)\\ n_{O_2}=\dfrac{4,48}{22,4}=0,2(mol)\\ b,m_{SO_2}=1,25.64=80(g)\\ V_{SO_2}=1,25.22,4=28(l)\\ m_{NH_3}=17.1,25=21,25(g)\\ V_{NH_3}=22,4.1,25=28(l)\)
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