\(\frac{1}{2}+\frac{1}{4}x=\frac{3}{2}\)
\(\frac{1}{4}x=\frac{3}{2}-\frac{1}{2}\)
\(\frac{1}{4}x=1\)
\(x=1:\frac{1}{4}\)
\(x=4\)
\(\frac{1}{2}\)+\(\frac{1}{4}\)x = \(\frac{3}{2}\)
=> \(\frac{1}{4}\)x = \(\frac{3}{2}\)- \(\frac{1}{2}\)
=> \(\frac{1}{4}\)x = 1
=> x = 1 : \(\frac{1}{4}\)
=> x = 4
Vậy x = 4
Ta có \(\frac{1}{2}+\frac{1}{4}x=\frac{3}{2}\)
\(\Rightarrow\frac{1}{4}x=\frac{3}{2}-\frac{1}{2}\)
\(\Rightarrow\frac{1}{4}x=1\)
\(\Rightarrow x=1.4\)
\(\Rightarrow x=4\)
\(\frac{1}{2}+\frac{1}{4}x=\frac{3}{2}\)
\(\frac{1}{4}x=\frac{3}{2}-\frac{1}{2}\)
\(\frac{1}{4}x=1\)
\(x=1:\frac{1}{4}\)
\(x=4\)