Question

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em cảm ơn trước

Answer 1

a) \(MgO+H_2SO_4\rightarrow MgSO_4+H_2O\)

\(n_{MgO}=\dfrac{6}{40}=0,15\left(mol\right)\)

TheoPT: \(n_{H_2SO_4}=n_{MgO}=0,15\left(mol\right)\)

\(\Rightarrow m_{H_2SO_4}=0,15.98=14,7\left(g\right)\)

b) \(m_{ddH_2SO_4}=50.1,2=60\left(g\right)\)

=> \(C\%_{H_2SO_4}=\dfrac{14,7}{60}.100=24,5\%\)

c) \(m_{ddsaupu}=6+60=66\left(g\right)\)

TheoPT: \(n_{MgSO_4}=n_{MgO}=0,15\left(mol\right)\)

=> \(C\%_{MgSO_4}=\dfrac{0,15.120}{66}.100=27,27\%\)