Question

Giúp em bài toán này với :

Bài 5: Tính :

d)\(\left(1-\frac{3}{4}\right)x\left(1+\frac{1}{3}\right):\left(1-\frac{1}{3}\right)\)=.............................................

                                                                     =.............................................

Answer 1

\(x = {-b \pm \sqrt{b^2-4ac} \over 2Ahs\)

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

Answer 2

\(d,\left(1-\frac{3}{4}\right)\left(1+\frac{1}{3}\right):\left(1-\frac{1}{3}\right)\)

\(=\frac{1}{4}.\frac{4}{3}.\frac{3}{2}\)

\(=\frac{1}{2}\)

Answer 3

\(=\left(1-\frac{3}{4}\right)x\left(1+\frac{1}{3}\right):\left(1-\frac{1}{3}\right)\)

\(=\frac{1}{4}x\frac{4}{3}:\frac{2}{3}\)

\(=\frac{4}{12}:\frac{2}{3}\)

\(=\frac{12}{24}\)

rút gọn là\(\frac{1}{2}\)