Giai pt sau : \(4\left(x^2+1\right)^2-\left(x^2-5x-2\right)^2=0\)
Giai PT:
\(x^2+6x+6+\left(\frac{x+3}{x+4}\right)^2=0\)
giải dùm mình mấy pt này vs !! mình chưa hc mấy pt bậc này mà thầy cho bt về nhà !! các bạn giúp mình vs !!!!
1/ \(x^3-3x^2+2=0\)
2/ \(2x^4-5x^3+6x^2-5x+2=0\)
3/ \(x\left(x+1\right)\left(x+2\right)\left(x+3\right)=24\)
4/ \(\left(x+1\right)^4+\left(x+3\right)^4=2\)
5/ \(x^5-5x^4+8x^3+8x^2-5x+1=0\)
GPT
\($x^4+\left(x+1\right)\left(5x^2-6x-6\right)=0$\)
Mn giúp mình vs
1, \(x^3-6x^2+10x-4=0\)
2, \(x^3+2x^2+2\sqrt{2}x+2\sqrt{2}=0\)
3, \(x^4+x^2-\sqrt{2}x+2=0
\)
4, \(x^4+5x^3-12x^2+5x+1=0\)
5, \(\left(x+5\right)\left(2x+12\right)\left(2x+20\right)\left(x+12\right)=3x^2\)
6, \(\left(x^2-5x+1\right)\left(x^2-4\right)=6\left(x-1\right)^2\)
7, \(x^4-9x^3+16x^2+18x+4=0\)
(1) giải pt quy về \(ax^2+bx+c=0\)
1) \(x^2=3x\) 2) \(x^2-3x=4\)
3) \(x^4-5x^2+6=0\) 4) \(x^3=9x\)
5) \(\left(x+2\right)\left(x-3\right)=x^2-4\) 6) \(\dfrac{x+11}{x^2-1}-\dfrac{x-1}{x+1}=\dfrac{2\left(x+7\right)}{x+1}\)
giúp mk vs mk cần gấp
giai pt sau
\(\sqrt{3x-1}-\sqrt{x+2}.\sqrt{3x^2+7x+2}+4=4x-2\)
\(x^2-5x+3.\sqrt{2x-1}=2.\sqrt{14-2x}+5\)
\(\left(x+1\right)\left(x+4\right)-3\sqrt{x^2+5x+2}=6\)
\(\left(x^2-5x+1\right)\left(x^2-4\right)=6\left(x-1\right)^2\) giải pt trên
GPT
\(x^4+\left(x+1\right)\left(5x^2-6x-6\right)=0\)