\(3x-7\sqrt{x}+4=0\)
\(\left(3x-3\sqrt{x}\right)-\left(4\sqrt{x}-4\right)=0\)
\(3\sqrt{x}\left(\sqrt{x}-1\right)-4\left(\sqrt{x}-1\right)=0\)
\(\left(\sqrt{x}-1\right)\left(3\sqrt{x}-4\right)=0\)
\(\orbr{\begin{cases}x=1\\x=\frac{16}{9}\end{cases}}.\)
Dễ mà:
3x-7Vx +4=3x-3Vx-4Vx+4=3Vx(Vx-1)-4Vx(Vx-1)=(Vx-1)(3Vx-4)=0
=>x=1,16/9
Note : V là căn