Đặt \(\sqrt[3]{x+1}=a;\sqrt[3]{7-x}=b\)
ta có \(a^3+b^3=x+1+7-x=8\) và a + b = 2 => a = 2 - b
thay vào ta có : \(\left(2-b\right)^3+b^3=2\) giả pt với ẩn b thay vào tìm x
giai pt
\(\sqrt{x+3}-\sqrt{x-1}=\sqrt{2x+2}\)
\(\sqrt{x^2-x+4}-x^2+x+2=0\)
\(\sqrt[3]{x+7}+\sqrt[3]{1-x}=2\)
giai pt
\(\sqrt{x+\frac{3}{x}}=\frac{x^2+7}{2\left(x+1\right)}\)
Giai pt \(\sqrt{3x+\sqrt{3}}-\sqrt{x-\sqrt{3}}=2\sqrt{x}\)
1. Giai cac pt sau:a, x-\(7\sqrt{x}\)\(+6\)\(=0\)b,\(\sqrt{x^2-9}\)\(-3\sqrt{x-3}\)=0
Giai PT:\(3+2\sqrt{x-x^2}=3\left(\sqrt{x}+\sqrt{1x}\right)\)
giai pt:
\(\sqrt{1-x^2}=(\frac{2}{3}-\sqrt{x})^2\)
giai pt :\(2x^3-x^2+\sqrt{2x^3-3x+1}=3x+1+\sqrt[3]{x^2+2}\)
GIAI PT
\(\sqrt{-x^2+4x+12}-\sqrt{-x^2+2x+3}=\sqrt{3}-x^2\)
Giai pt\(2+\sqrt{4-3\sqrt{10-x}}=\frac{x}{3}\)
