\(x=\frac{1}{2}x+\frac{1}{4}x+\frac{1}{7}x+3\)
\(\Rightarrow x=x\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{7}\right)+3\)
\(\Rightarrow x=\frac{25}{28}x+3\Rightarrow x-\frac{25}{28}x=3\Rightarrow x\left(1-\frac{25}{28}\right)=3\Rightarrow x.\frac{3}{28}=3\Rightarrow x=28\)
Vậy x = 28
Đặt x làm nhân tử chung : x(1/2+1/4+1/7)+3=x
Qui đồng cái tổng đấy chuyển vế là ra
\(\frac{1}{2}x+\frac{1}{4}x+\frac{1}{7}x+3=x\)
<=>x(1/2+1/4+1/7)+3=x
<=>x(14/28+7/28+4/28)+3=x
<=>x28/28(14/28+7/28+4/28)+84/28=x.28/28
=>x.28(14+7+4)+84=x.28
<=>x.28.25+84=x.28
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