2x3+5x2=7x
-7x+5x2+2x3=7x+(-7x)
ta có 7x+(-7x)
-7x + 5x2 + 2x3 = 0
x(-7 + 5x + 2x2) = 0
x[(-7 + -2x)(1 + -1x)] = 0
2x^3 + 5x^2 = 7x
<=> 2x^3 + 5x^2 - 7x = 0
<=> x(2x^2 + 5x - 7) = 0
<=> x(2x^2 + 7x - 2x - 7) = 0
<=> x[x(2x + 7) - (2x + 7)] = 0
<=> x(x - 1)(2x + 7) = 0
<=> x = 0 hoặc x - 1 = 0 hoặc 2x + 7 = 0
<=> x = 0 hoặc x = 1 hoặc x = -7/2