Đặt \(\sqrt{x}=a;\sqrt{x+5}=b\) (a, b >=0)
=> \(a^2+b+a+ab=20\)
<=> (a+1)(a+b)=20
Với a, b nguyên => thuộc Ư(20)=1,2,4,5,10,20
Với a, b ko nguyên thì chịu
giai phuong trinh : \(2x^2\left(5-\sqrt[3]{5x-x^3}\right)=2x^3+17x-8\)
giai phuong trinh \(\sqrt[3]{x+1}+\sqrt[3]{x-1}=\sqrt[3]{5x}\)
giai phuong trinh:\(\sqrt{4x^2+5x+1}\) -2\(\sqrt{x^2-x-1}\)=3-9x
giai phuong trinh \(\sqrt{8+\sqrt{x-3}}+\sqrt{5-\sqrt{x-3}=5}\)
Giai phuong trinh
\(\sqrt{x-\sqrt{x-2}}+\sqrt{x+\sqrt{x-2}}=3\)
\(\sqrt{x-1+2\sqrt{x-2}}+\sqrt{x-1-2\sqrt{x-2}}giai~phuong\cdot trinh'\)
Giai phuong trinh : \(\frac{2+\sqrt{x}}{\sqrt{2}+\sqrt{\sqrt{x}+2}}+\frac{2-\sqrt{x}}{\sqrt{2}-\sqrt{2-\sqrt{x}}}=\sqrt{2}\)
giai phuong trinh \(\sqrt{2x^2+11x+19}+\sqrt{2x^2+5x+7}=3\left(x+2\right)\)
Giai phuong trinh: \(\sqrt{x^2+12}+17=9x+\sqrt{x^2+5}.\)
