Question

Giải phương trình: \(x^4-2x^2+7x-12=0\)

Answer 1

https://olm.vn/hoi-dap/tim-kiem?id=222064489607&id_subject=1&q=+++++++++++Gi%E1%BA%A3i+ph%C6%B0%C6%A1ng+tr%C3%ACnh:+x4%E2%88%922x2+7x%E2%88%9212=0++++++++++

Answer 2

x⁴ - 2x² + 7x - 12 = 0

( x⁴ - x³ + 3x² ) + ( x³ - x² + 3x ) - ( 4x² - 4x + 12 ) = 0

x² ( x² - x + 3 ) + x . ( x² - x + 3 ) - 4 ( x² - x + 3 ) = 0

( x² + x - 4 ) ( x² - x + 3 ) = 0

\(\Rightarrow x^2+x-4=0\)

\(\Rightarrow x=\frac{-1\mp\sqrt{17}}{2}\)