Question

Giải phương trình sau:

\(x+\frac{x+1}{2}+\frac{x+2}{3}+\frac{x+3}{4}=1\) 

Answer 1

x=-0,44

Answer 2

\(x+\frac{x+1}{2}+\frac{x+2}{3}+\frac{x+3}{4}=1\)

\(\Rightarrow\frac{12x}{12}+\frac{6x+6}{12}+\frac{4x+8}{12}+\frac{3x+9}{12}=\frac{12}{12}\)

\(\Rightarrow25x+23=12\)

\(\Rightarrow x=\frac{-11}{25}\)

Answer 3

\(x+\frac{x+1}{2}+\frac{x+2}{3}+\frac{x+3}{4}=1\)

\(\Rightarrow\frac{12x+6\left(x+1\right)+4\left(x+2\right)+3\left(x+3\right)}{12}=1\)

\(\Rightarrow\frac{12x+6x+6+4x+8+3x+9}{12}=1\)

\(\Rightarrow\frac{25x+23}{12}=1\Rightarrow25x+23=12\Rightarrow x=-\frac{11}{25}\)

Vậy \(x=-\frac{11}{25}\)