Question

giải phương trình sau

(x-3)-\(\frac{\left(x-3\right)\left(2x-5\right)}{6}=\frac{\left(x-3\right)\left(3-x\right)}{4}\)

Answer 1

\(\Leftrightarrow\frac{12\left(x-3\right)-2\left[\left(x-3\right)\left(2x-5\right)\right]}{12}=\frac{3\left[\left(x-3\right)\left(3-x\right)\right]}{12}\)

\(\Leftrightarrow12x-36-2\left(2x^2-5x-6x+15\right)=3\left(3x-x^2-9+3x\right)\)

\(\Leftrightarrow12x-36-4x^2+10x+12x-30=9x-3x^2-27+9x\)

\(\Leftrightarrow-x^2+34x-39=0\)

\(\Leftrightarrow-\left(x-17\right)^2-250=0\)

\(\Leftrightarrow-\left(x-17\right)^2=250\left(voly\right)\)

vay \(S=\varnothing\)