\(\frac{4x+3}{5}-\frac{6x-2}{7}=\frac{5x+4}{3}+3\)
\(\Leftrightarrow\frac{4x+3}{5}+1+\frac{2-6x}{7}-2=\frac{5x+4}{3}+2\)
\(\Leftrightarrow\frac{4x+3}{5}+\frac{5}{5}+\frac{2-6x}{7}-\frac{14}{7}=\frac{5x+4}{3}+\frac{6}{3}\)
\(\Leftrightarrow\frac{4x+8}{5}+\frac{-6x-12}{7}=\frac{5x+10}{3}\)
\(\Leftrightarrow\frac{4x+8}{5}+\frac{-6x-12}{7}-\frac{5x+10}{3}=0\)
\(\Leftrightarrow\frac{4.\left(x+2\right)}{5}+\frac{-6.\left(x+2\right)}{7}-\frac{5.\left(x-2\right)}{3}=0\)
\(\Leftrightarrow\left(x+2\right).\left(\frac{4}{5}+\frac{-6}{7}-\frac{5}{3}\right)=0\)
<=>x+2=0 \(\left(\text{vì: }\frac{4}{5}+\frac{-6}{7}-\frac{5}{3}\ne0\right)\)
<=>x=-2
Vậy S={-2}
Bạn quy đồng cho mẫu số giống nhau rồi bắt đầu khử mẫu, tính như bình thường nha.
