\(x^2+42=4320\)
\(\Rightarrow x^2+90x-48x-4320=0\)
\(\Rightarrow x\left(x+90\right)-48\left(x-90\right)\)
\(\Rightarrow\left(x+90\right)\left(x-48\right)\)
\(\Rightarrow\orbr{\begin{cases}x+90=0\\x-48=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-90\\x=48\end{cases}}}\)
Ta có x^2+42x=4320
=>x^2+90x-48x-4320=0
=>x(x+90)-48(x+90)=0
=>(x-48)(x+90)=0
=>x=48 hoặc x=-90