\(\hept{\begin{cases}x^3+y=2\\y^3+x=2\end{cases}\Leftrightarrow\hept{\begin{cases}x-y=0\\x^2+xy+y^2+1=0\end{cases}}\Leftrightarrow\hept{\begin{cases}x=y\\\left(x+\frac{1}{2}y\right)^2+\frac{3}{4}y^2+1=0=>\end{cases}vo.nghiem}}\)
x=y=> x^3+x=2<=> x^2(x-1)+2(x-1)=0\(\hept{\begin{cases}x-1=0=>x=1\\x^2+1=0\left(vo.nghiem\right)\end{cases}}\)
x=y=1