Ta có : x - y = 2 => x=2+y (1)
Mà 5x-3y=10 (2)
Thay (1) vào (2) ta dc : 5(2+y) - 3y =10
=> y = 0
=> x =0+2=2
\(5x-3y=10\)
\(\Leftrightarrow3\left(x-y\right)+2x=10\)
\(\Leftrightarrow6+2x=10\)
\(\Leftrightarrow x=2\)
\(\Leftrightarrow\hept{\begin{cases}5x-3y=10\\x-y=2\end{cases}}\)
\(\Rightarrow4x-2y=8\Rightarrow2x-y=4\)
\(\Rightarrow y=2x-4\)
Thay : \(x-2x+4=2\)
\(\Rightarrow x=2\)
\(\Rightarrow y=0\)
\(\hept{\begin{cases}x-y=2\\5x-3y=10\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}x=y+2\\5x-3y=10\end{cases}}\)
\(\Rightarrow5\left(y+2\right)-3y=10\)
\(\Leftrightarrow5y+10-3y=10\Leftrightarrow2y=0\Leftrightarrow y=0\)
\(\Rightarrow x=0+2=2\)
Vậy nghiệm của hpt là (2; 0)
