dễ mà bạn
a)3x-18=0 à mà mik chx hc phương trình
3x=18+0 sorry bạn nhé
3x=18
x=18:3
x=6
vậy x=6
a)\(3x-18=0\)
\(\Leftrightarrow3x=18\)
\(\Leftrightarrow x=6\)
Vậy x=6
b)\(2x.\left(x-4\right)-3x+12=0\)
\(\Leftrightarrow2x.\left(x-4\right)-3\left(x-4\right)=0\)
\(\Leftrightarrow\left(2x-3\right).\left(x-4\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}2x-3=0\\x-4=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=4\end{cases}}}\)
Vậy .......
c)\(\frac{x-1}{2}-\frac{x+3}{3}=x+1\)
\(\Leftrightarrow6.\left(\frac{x-1}{2}-\frac{x+3}{3}\right)=6.\left(x+1\right)\)
\(\Leftrightarrow3.\left(x-1\right)-2.\left(x+3\right)=6x+6\)
\(\Leftrightarrow3x-3-2x-6=6x+6\)
\(\Leftrightarrow3x-2x-6x=6+3+6\)
\(\Leftrightarrow-5x=15\)
\(\Leftrightarrow x=-3\)
Vậy x= -3
d)\(\frac{x-3}{x+3}-\frac{5}{3-x}=\frac{30}{x^2-9}\)
\(\Leftrightarrow\frac{x-3}{x+3}-\frac{-5}{x-3}=\frac{30}{\left(x+3\right).\left(x-3\right)}\)
\(\Leftrightarrow\frac{\left(x-3\right).\left(x-3\right)}{\left(x+3\right).\left(x-3\right)}-\frac{-5.\left(x+3\right)}{\left(x-3\right).\left(x+3\right)}=\frac{30}{\left(x-3\right).\left(x+3\right)}\)
\(\Leftrightarrow\left(x-3\right)^2-\left(-5\right).\left(x+3\right)=30\)
\(\Leftrightarrow x^2-6x+9-\left(-5x-15\right)=30\)
\(\Leftrightarrow x^2-6x+9+5x+15-30=0\)
\(\Leftrightarrow x^2-x-6=0\)
\(\Leftrightarrow x^2-3x+2x-6=0\)
\(\Leftrightarrow x.\left(x-3\right)+2.\left(x-3\right)=0\)
\(\Leftrightarrow\left(x+2\right).\left(x-3\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x+2=0\\x-3=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-2\\x=3\end{cases}}}\)
Vậy......
Câu d)
ĐKXĐ:\(x\ne\pm3\)
Cái x=3 loại
Lấy cái x=-2
\(a\))\(3x-18=0\)
\(\Leftrightarrow3.\left(x-6\right)=0\)
\(\Leftrightarrow x-6=0\)
\(\Leftrightarrow x=6\)
vậy tập nghiệm của phương trình là \(S=\left\{6\right\}\)
b)\(2x.\left(x-4\right)-3x+12=0\)
\(\Leftrightarrow2x.\left(x-4\right)-3\left(x-4\right)=0\)
\(\Leftrightarrow\left(2x-3\right).\left(x-4\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}2x-3=0\\x-4=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=4\end{cases}}\)
vậy..........................
c)\(\frac{x-1}{2}-\frac{x+3}{3}=x+1\)
\(\Leftrightarrow\frac{3.\left(x-1\right)}{6}-\frac{2.\left(x+3\right)}{3}=\frac{6.\left(x+1\right)}{6}\)
\(\Leftrightarrow3.\left(x-1\right)-2.\left(x+3\right)=6.\left(x+1\right)\)
\(\Leftrightarrow3x-3-2x-6=6x+6\)
\(\Leftrightarrow3x-2x-6x=6+3+6\)
\(\Leftrightarrow-5x=15\)
\(\Leftrightarrow x=-3\)
vậy..............
