\(3^x+25=26\cdot2^2+2\cdot3^0\)
\(3^x+25=26\cdot4+2\cdot1\)
\(3^x+25=104+2\)
\(3^x+25=106\)
\(3^x=106-25\)
\(3^x=81\)
\(3^x=3^4\)
Vậy : \(x=4\)
\(27\cdot3^x=243\)
\(3^x=\frac{243}{27}\)
\(3^x=9\)
\(3^x=3^2\)
Vậy x = 2
\(3^x+25=26\times2^2+2\times3^0\)
\(\Rightarrow3^x+25=26\times4+2\times1\)
\(\Rightarrow3^x+25=104+2\)
\(\Rightarrow3^x+25=106\)
\(\Rightarrow3^x=81\left(\text{cùng bớt đi 25}\right)\)
\(\Rightarrow3^x=3^4\)
\(\Rightarrow x=4\)
\(27\times3^x=243\)
\(\Rightarrow3^3\times3^x=3^5\)
\(\Rightarrow3^{3+x}=3^5\)
\(\Rightarrow3+x=5\)
\(\Rightarrow x=2\left(\text{cùng bớt đi 3}\right)\)
