a) \(\dfrac{x}{x-3}+\dfrac{9-6x}{x^2-3x}=\dfrac{x}{x-3}+\dfrac{9-6x}{x\left(x-3\right)}=\dfrac{x^2+9-6x}{x\left(x-3\right)}=\dfrac{\left(x-3\right)^2}{x\left(x-3\right)}=\dfrac{x-3}{x}\)
b) \(\dfrac{x+2}{3x}+\dfrac{x-5}{5x}+\dfrac{x+8}{4x}=\dfrac{20\left(x+2\right)+12\left(x-5\right)+15\left(x+8\right)}{60x}=\dfrac{47x+100}{60x}\)
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