a,x-10/1994+x-8/1996+x-6/1998+x-4/2000+x-2/2002=x-2002/2+x-2000/4+x-1998/6+x-1996/8+x-1994/10
b,x-1991/9+x-1993/7+x-1995/5+x-1997/3+x-1999/1=x-9/1991+x-7/1993+x-5/1995+x-3/1997+x-1/1999
c,x-1/13-2x-13/15=3x-15/27-4x-27/29
giải phương trình
a) \(\dfrac{x+1}{2015}+\dfrac{x+2}{2014}=\dfrac{x+3}{2013}+\dfrac{x+4}{2012}\)
b) \(\dfrac{x-85}{15}+\dfrac{x-74}{13}+\dfrac{x-67}{11}+\dfrac{x-64}{9}=10\)
giải chi tiết giúp e ạ;-;
Giải các phương trình sau : ( biến đổi đặc biệt )
a) \(\frac{x+1}{35}\)+ \(\frac{x+3}{33}\)= \(\frac{x+5}{31}\)+ \(\frac{x+7}{29}\)( HD : cộng thêm 1 vào các hạng tử )
b) \(\frac{x-10}{1994}\)+ \(\frac{x-8}{1996}\)+\(\frac{x-6}{1998}\)+ \(\frac{x-4}{2000}\)+ \(\frac{x-2}{2002}\)= \(\frac{x-2002}{2}\)+ \(\frac{x-2000}{4}\)+ \(\frac{x-1988}{6}\)+ \(\frac{x-1996}{8}\)+ \(\frac{x-1994}{10}\)( HD : trừ đi 1 vào các hạng tử )
c) \(\frac{x-1991}{9}\)+ \(\frac{x-1993}{7}\)+ \(\frac{x-1995}{5}\)+ \(\frac{x-1997}{3}\)+ \(\frac{x-1991}{1}\)= \(\frac{x-9}{1991}\)+ \(\frac{x-7}{1993}\)+ \(\frac{x-5}{1995}\)+ \(\frac{x-3}{1997}\)+ \(\frac{x-1}{1999}\)( HD : trừ đi 1 vào các hạng tử )
d) \(\frac{x-85}{15}\)+ \(\frac{x-74}{13}\)+ \(\frac{x-67}{11}\)+ \(\frac{x-64}{9}\)= 10 ( Chú ý : 10 = 1 + 2 + 3 + 4 )
e) \(\frac{x-1}{13}\)- \(\frac{2x-13}{15}\)= \(\frac{3x-15}{27}\)- \(\frac{4x-27}{29}\)( HD : Thêm hoặc bớt 1 vào các hạng tử )
Giải các phương trình sau
1) \(\frac{x-85}{15}+\frac{x-74}{13}+\frac{x-67}{11}+\frac{x-64}{9}=10\)
2)\(\frac{x-1}{13}-\frac{2x-13}{15}=\frac{3x-15}{27}-\frac{4x-27}{29}\)
3)\(\frac{1909-x}{91}+\frac{1907-x}{93}+\frac{1905-x}{95}+\frac{1903-x}{91}+4=0\)
4)\(\frac{x-90}{10}+\frac{x-76}{12}+\frac{x-58}{14}+\frac{x-36}{16}+\frac{x-15}{17}=15\)
\(\frac{x+6}{1999}\)+ \(\frac{x+8}{1997}\)= \(\frac{x+10}{1995}\)+ \(\frac{x+12}{1993}\)
Giải phương trình sau :
\(\frac{x-85}{15}\)+\(\frac{x-74}{13}+\frac{x-67}{11}+\frac{x-64}{9}=10\)(HD:10=1+2+3+4)
Giải phương trình
\(\frac{x+1}{2003}+\frac{x+3}{2001}+\frac{x+5}{1999}=\frac{x+7}{1997}+\frac{x+9}{1995}+\frac{x+11}{1993}\)
Giải phương trình
\(\frac{x+1}{2003}+\frac{x+3}{2001}+\frac{x+5}{1999}-\frac{x+7}{1997}-\frac{x+9}{1995}-\frac{x+11}{1993}=0\)
\(\frac{x-1991}{9}+\frac{x-1993}{7}+\frac{x-1995}{5}+\frac{x-1997}{3}+\frac{x-1999}{1}=\frac{x-9}{1991}+\frac{x-7}{1993}+\frac{x-5}{1995}+\frac{x-3}{1997}+\frac{x-1}{1999}\)