Question

Giai bat phuong trinh sau

​\(\frac{2x+1}{x-3}\)>1

Answer 1

=> 2x +1 > x - 3

=> 2x - x > -3 - 1

=> x> -4

Answer 2

\(\frac{2x+1}{x-3}>1\)

\(\Leftrightarrow2x+1>x-3\)

\(\Leftrightarrow2x-x>-3-1\)

\(\Leftrightarrow x>-4\)

Answer 3

\(\frac{2x+1}{x-3}\)>1

<=> 2x+1 > x-3

<=> 2x-x >-3-1

<=> x > -4

Vậy BPT có tập No S= \(\hept{\begin{cases}x\\x>4\end{cases}}\)

Answer 4

\(\frac{2x+1}{x-3}>1\)

\(\Rightarrow\frac{2x+1}{x-3}>\frac{x-3}{x-3}\)

\(\Rightarrow2x+1>x-3\)

\(\Rightarrow2x-x>-1-3\)

\(\Rightarrow x>-4\)

\(\Rightarrow S=\left\{x\in R;x>-4\right\}\)