tl
333300 nha
HT
k em với
Gọi biểu thức trên là A
A = 1x2 + 2x3 + 3x4 + 4x5 + ...+ 99x100
A x 3 = 1x2x3 + 2x3x3 + 3x4x3 + 4x5x3 + ... + 99x100x3
A x 3 = 1x2x3 + 2x3x(4-1) + 3x4x(5-2) + 4x5x(6-3) + ... + 99x100x(101-98)
B x 3 = 1x2x3 + 2x3x4 - 1x2x3 + 3x4x5 - 2x3x4 + 4x5x6 - 3x4x5 + ... + 99x100x101 - 98x99x100.
A x 3 = 99x100x101
A = 99x100x101 : 3
A = 333300
=)
Đặt \(A = 1 . 2 + 2.3 + ... + 99.100\)
\(⇒ 3 A = 1.2 .3 + 2.3 .3 + ... + 99.100 .3\)
\(⇒ 3 A = 1.2 . ( 3 − 0 ) + 2.3 . ( 4 − 1 ) + ... + 99.100 . ( 101 − 98 )\)
\(⇒ 3 A = 1.2 .3 − 0.1 .2 + 2.3 .4 − 1.2 .3 + ... + 99.100 . 101 − 98.99 .100\)
\(⇒ 3 A = 0.1 .2 + 99.100 .101\)
\(⇒ 3 A = 999900\)
\(⇒ A = 999900 : 3\)
\(⇒ A = 333300\)
\(Vậy A = 333300\)
Nguyễn bình nguyên cop mạng
bằng 333300 nha
TL:
333300 nhé anh
Ok nhaaaaaaaaaaaaaaaaaaaaaaaaaaaa
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