\(|x+1|+|x+2|+|x+3|=2006x\)
Xét x< 0:
\(\Rightarrow\)2006x< 0 mà vế trái > 0, mâu thuẫn
\(\Rightarrow\)x > 0
Với x > 0 ta có: |x+1|+|x+2|+|x+3|= x+ 1+ x+ 2+ x+ 3
\(\Rightarrow\)x+ 1+ x+ 2+ x+ 3= 2006x
3x+ 6= 2006x
6=2006x- 3x
6=2003x
x= \(\frac{6}{2003}\)