Question

 Giá trị của x²⁰¹⁴ biết x thỏa mãn \(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)

 P/s : Rảh nên đăng, nhanh tk cho. 3tk :) 

Answer 1

x+1/10+x+1/11+x+1/12-x+1/13+x+1/14=0

x+1(1/10+1/11+1/12-1/13-1/14)=0

x+1(a)=0

vi a khac 0 nen x+1 bang 0

suy ra x bang -1

x mu 2014 bang 1

Answer 2

sai cai gi co dung ma

Answer 3

\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)\(\Leftrightarrow\)\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}-\frac{x+1}{13}-\frac{x+1}{14}=0\)

\(\Leftrightarrow\left(x+1\right)\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)=0\Leftrightarrow x+1=0\Leftrightarrow x=-1\). Suy ra:

\(x^{2014}=\left(-1\right)^{2014}=1.\)

Answer 4

x+1/10+x+1/11+x+1/12-x+1/13+x+1/14=0

x+1(1/10+1/11+1/12-1/13-1/14)=0

x+1(a)=0

vi a khac 0 nen x+1 bang 0

suy ra x bang -1

x mu 2014 bang 1

Answer 5

\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)

\(\Rightarrow\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}-\frac{x+1}{13}-\frac{x+1}{14}=0\)

\(\Rightarrow\left(x+1\right)\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)=0\Leftrightarrow x+1=0\rightarrow x=-1\)

\(\Rightarrow x^{2014}=\left(-1\right)^{2014}=1.\)

K tui nha bà Vy

Answer 6

\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}-\frac{x+1}{13}-\frac{x+1}{14}=0\)

\(\left(x+1\right)\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)=0\)

Vì \(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\)khác 0 nên x + 1 = 0 

=> x = -1

\(x^{2014}=\left(-1\right)^{2014}=1\) 

Answer 7

cậu học lớp 6 à