b) (7x -11)^3 = 26.2^2 + 2.3^0
(7x -11)^3 = (26).(4) + (2).(1) = 106
(7x -11) = ³√106
7x = 11 + (³√106)
x = (1/7)(11 + ³√106)
x ≈ 2,25
x không thuộc N
gia su x=a/m, y=b/m (a,b,m thuoc z, m>0) va x<y.hay chung to rang neu chon z=a+b/2m thi ta co x<z<y.
minh moi hoc lop 7 minh ko hieu bai nay ai giai giup minh voi
Gia su x = a/m;y = b/m (a;b;m thuoc Z;m>0) va x< y. Hay chung to rang neu chon z = a+b/2m thi ta co x<y<z
Gia su \(x=\frac{a}{m},y=\frac{b}{m}\)va x<y.Hay chung to rang neu chon \(z=\frac{a+b}{2m}\)thi ta co x<y<z
Su dung tinh chat neu a,b,c thuoc zva a<b thi a+c<b+c
giup mik voi nha tik cho cam on
giả su x =a/m , y = b/m (a,b thuoc z, m >0) va x <y. hay chung to rang neu chon z=a+b/2m thi ta co x<z <y
giai gium minh voi
gia su x=a/m. y=b/m (a,b,m la so nguyen, m>0) va x<y. hay chung to rang neu chon z=a+b/2m thi ta co x<z<y
gia su x=a/m,y=b/m(a,b,m€z,m>0,x<y)
hay chung to rang neu chon Z=a+b/2•m thi ta co x<z<y
G/s x = \(\frac{a}{m}\) , y = \(\frac{b}{m}\) ( a, b, m \(\in Z\) , m > 0 ) , x < y . Hay chung to rang neu chon z= \(\frac{a+b}{2m}\) thi ta co x < z < y .
gia su x=a/m , y=b/m ( a, m, b € z,m > 0) va x < y . hay chung to răng nêu chon z =a+b / 2x m thi taco x<z<y
Cho:x=a/m, y=b/m, z=a+b/2m(a,b,m thuoc Z, m khac 0)Chung to :x<z<y
