Question

\(\frac{x}{4}+\frac{9}{8}=\frac{7}{12}\)

Answer 1

\(\frac{x}{4}+\frac{9}{8}=\frac{7}{12}\)

\(\frac{x}{4}=\frac{7}{12}-\frac{9}{8}\)

\(\frac{x}{4}=\frac{-13}{24}\)

\(\Leftrightarrow24.x=\left(-13\right).4\)

\(\Leftrightarrow24.x=-52\)

\(\Leftrightarrow x=\left(-52\right):24\)

\(\Leftrightarrow x=\frac{-13}{6}\)

Answer 2

\(\frac{x}{4}+\frac{9}{8}=\frac{7}{12}\)=> \(\frac{x}{4}=\frac{7}{12}-\frac{9}{8}\)

=> \(\frac{x}{4}=\frac{14}{24}-\frac{27}{24}\)=\(\frac{-13}{24}\)=> \(24x=-52\)=> x=\(\frac{-52}{24}=\frac{-13}{6}\)

vậy x=\(\frac{-13}{6}\)

Answer 3

\(\frac{x}{4}+\frac{9}{8}=\frac{7}{12}\)

           \(\frac{x}{4}=\frac{7}{12}-\frac{9}{8}\) 

            \(\frac{x}{4}=-\frac{13}{24}\)

             \(\frac{6x}{24}=-\frac{13}{24}\)

           =>6x=-13

                x=-13:6

                x=\(-\frac{13}{6}\)

  vậy x=\(-\frac{13}{6}\)