Giải phương trình
\(\frac{x+24}{1996}+\frac{x+25}{1995}+\frac{x+26}{1994}+\frac{x+27}{1993}+\frac{x+2036}{4}=0\)
Giải phương trình sau
\(\frac{x+24}{1996}+\frac{x+25}{1995}+\frac{x+26}{1994}+\frac{x+27}{1993}=0\)
Tìm x biết \(\frac{x+24}{1996}+\frac{x+25}{1995}+\frac{x+26}{1994}+\frac{x+27}{1993}+\frac{x+2036}{4}=0\)
xin ghi ro cach lam
Giải PT\(\frac{x-29}{1986}+\frac{x-27}{1988}+\frac{x-25}{1990}+\frac{x-23}{1992}+\frac{x-21}{1994}+\frac{x-19}{1996}=\frac{x-1986}{29}+\frac{x-1988}{27}+\frac{x-1990}{25}+\frac{x-1992}{23}+\frac{x-1994}{21}+\frac{x-1996}{19}\)
Giải bất phương trình sau:
\(\frac{x+1994}{2009}+\frac{x+1995}{2010}>\frac{x+1996}{2011}+\frac{x+1997}{2012}\)
Giải các phương trình:
\(\dfrac{x+24}{1996}+\dfrac{x+25}{1995}+\dfrac{x+26}{1994}+\dfrac{x+27}{1993}+\dfrac{x+2036}{4}=0\)
\(\frac{x-1991}{9}+\frac{x-1993}{7}+\frac{x-1995}{5}+\frac{x-1997}{3}+\frac{x-1999}{1}=\frac{x-9}{1991}+\frac{x-7}{1993}+\frac{x-5}{1995}+\frac{x-3}{1997}+\frac{x-1}{1999}\)
Giải các phương trình sau : ( biến đổi đặc biệt )
a) \(\frac{x+1}{35}\)+ \(\frac{x+3}{33}\)= \(\frac{x+5}{31}\)+ \(\frac{x+7}{29}\)( HD : cộng thêm 1 vào các hạng tử )
b) \(\frac{x-10}{1994}\)+ \(\frac{x-8}{1996}\)+\(\frac{x-6}{1998}\)+ \(\frac{x-4}{2000}\)+ \(\frac{x-2}{2002}\)= \(\frac{x-2002}{2}\)+ \(\frac{x-2000}{4}\)+ \(\frac{x-1988}{6}\)+ \(\frac{x-1996}{8}\)+ \(\frac{x-1994}{10}\)( HD : trừ đi 1 vào các hạng tử )
c) \(\frac{x-1991}{9}\)+ \(\frac{x-1993}{7}\)+ \(\frac{x-1995}{5}\)+ \(\frac{x-1997}{3}\)+ \(\frac{x-1991}{1}\)= \(\frac{x-9}{1991}\)+ \(\frac{x-7}{1993}\)+ \(\frac{x-5}{1995}\)+ \(\frac{x-3}{1997}\)+ \(\frac{x-1}{1999}\)( HD : trừ đi 1 vào các hạng tử )
d) \(\frac{x-85}{15}\)+ \(\frac{x-74}{13}\)+ \(\frac{x-67}{11}\)+ \(\frac{x-64}{9}\)= 10 ( Chú ý : 10 = 1 + 2 + 3 + 4 )
e) \(\frac{x-1}{13}\)- \(\frac{2x-13}{15}\)= \(\frac{3x-15}{27}\)- \(\frac{4x-27}{29}\)( HD : Thêm hoặc bớt 1 vào các hạng tử )
a) \(\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\)
\(\Leftrightarrow\frac{x-23}{24}+\frac{x-23}{25}-\frac{x-23}{26}-\frac{x-23}{27}=0\)
\(\Leftrightarrow\left(x-23\right)\left(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\right)=0\)
\(\Leftrightarrow x-23=0\)( vì \(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\ne0\))
\(\Leftrightarrow x=23\)
Vậy nghiệm của pt x=23