\(\Leftrightarrow\left(x+1\right)\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)=0\)
vì \(\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)\ne0\)
=> x+1 =0 => x =-1
Tìm x:
\(\frac{X+1}{10}+\frac{X+1}{11}+\frac{X+1}{12}=\frac{X+1}{13}+\frac{X+1}{14}\)
Tìm x , biết : \(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
\(\frac{X+1}{10}+\frac{X+1}{11}+\frac{X+1}{12}=\frac{X+1}{13}+\frac{X+1}{14}\)
Tìm x
Tìm X biết
\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
tìm x biết
\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
Tìm x biết:
\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
tìm x: \(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}+\frac{x+1}{15}\)
Tìm x,biết:
\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
\(|\frac{x+1}{10}|+|\frac{x+1}{11}|+|\frac{x+1}{12}|+|\frac{x+1}{13}|+|\frac{x+1}{14}|\)
Hãy tìm x
