=> \(\frac{x-1}{x+5}-2>0\Rightarrow\frac{\left(x-1\right)-2\left(x+5\right)}{x+5}>0\Rightarrow\frac{-x-11}{x+5}>0\)
=> - (x + 11). (x + 5) > 0 => (x +11).(x+ 5) < 0 => x + 11 và x + 5 trái dấu
Nhận xét: x+ 11 > x + 5 nên nếu x+ 11 và x+ 5 trái dấu thì x + 11 > 0 và x + 5 < 0
=> x> -11 và x < -5
Vậy -11 < x < -5
Nếu x nguyên thì x = -10; -9; -8;...; -6
1) \(\frac{24}{-12}=\frac{x}{5}=\frac{-y}{3}\)Tìm x và y
2) \(\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-5}{25}\le\frac{x}{10}< \frac{-3}{4}+\frac{4}{14}+\frac{-2}{8}+\frac{-3}{5}+\frac{5}{7}\)Tìm x
3) \(\frac{8.x+18}{2.x+6}\)Tìm x
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
\(-5\left(x+\frac{1}{5}\right)-\frac{1}{2}\left(x-\frac{2}{3}\right)=\frac{3}{2}x-\frac{5}{6}\)
tìm x
Tìm x
\(\left(-5\right)\left(x+\frac{1}{5}\right)-\frac{1}{2}\left(x-\frac{2}{3}\right)=\frac{3}{2}x-\frac{5}{6}\)
tìm x
\(x-\frac{3}{4}-x\cdot\frac{2}{3}+x:\frac{1}{2}-x:\frac{2}{5}=\frac{11}{4}\)
\(\frac{x}{5}-\frac{2}{x-1}=\frac{2}{15}\)
Tìm x biết :
a, \(\frac{1}{3}.x+\frac{2}{5}.\left(x-1\right)=0\)
b,\(3.\left(x-\frac{1}{2}\right)-5.\left(x+\frac{3}{5}\right)=x+\frac{1}{5}\)
1.Tìm số nguyên x biết
\(\frac{x-2}{27}+\frac{x-3}{26}+\frac{x-4}{25}+\frac{x-5}{24}+\frac{x-44}{5}=1\)
2.tìm các số nguyên x, y thỏa mãn
\(\frac{x}{2}+\frac{x}{y}-\frac{3}{2}=\frac{10}{y}\)
Mình đang cần gấp! Cảm ơn nhiều
Tìm x:
a)\(\left(3x-1\right)\left(-\frac{1}{2}x+5\right)=0\)
b)\(-5\left(x+\frac{1}{5}\right)-\frac{1}{2}\left(x-\frac{2}{3}\right)=\frac{3}{2}x-\frac{5}{6}\)
Tìm x
a, \(\frac{x}{2}+\frac{x}{3}+\frac{x}{5}-\frac{1}{3}=\frac{2}{15}\)
b, x + 2 + x +3 + x +5 = 28
c, { x + 1 } + { x + 2 } + .........+ { x + 9 } = 45
