\(\frac{x-1}{2}=\frac{2.\left(x-1\right)}{2.2}=\frac{2x-2}{4}\)
\(\frac{y-2}{3}=\frac{3.\left(y-2\right)}{3.3}=\frac{3y-6}{9}\)
Theo t/c dãy tỉ số bằng nhau:
\(\frac{2x-2}{4}=\frac{3y-6}{9}=\frac{z-3}{4}=\frac{2x-2+3y-6-z+3}{4+9-4}=\frac{50-5}{9}=\frac{45}{9}=5\)
=> \(\frac{x-1}{2}=5\Rightarrow x-1=10\Rightarrow x=11\)
=> \(\frac{y-2}{3}=5\Rightarrow y-2=15\Rightarrow y=17\)
=> \(\frac{z-3}{4}=5\Rightarrow z-3=20\Rightarrow z=23\)
(2x-2)/4 = (3y-6)/9 =(z-3)/4
(2x+3y -z -5)/10 = (50-5)/10 = 4,5
x -1 = 4,5.2 = 9
x = 10
y-2 = 4,5.3 = 13,5
y = 15,5
z-3 = 4,5.4 = 18
z = 21
chị minh hiền làm đúng rùi, mk nhầm 13 -4 =10