\(\frac{63452+x}{36548+x}=\frac{23}{77}\)
\(\Rightarrow77\left(63452+x\right)=23\left(36548+x\right)\)
\(4885804+77x=840604+23x\)
\(77x-23x=840604-4885804\)
\(54x=-4045200\)
\(x=-4045200:54\)
\(x=-74911,11111\)
Vậy.....................................................
Ta có \(\frac{63452+x}{36528+x}=\frac{23}{77}\Leftrightarrow\frac{36528+x+26924}{36528+x}=\frac{23}{77}\)
\(\Leftrightarrow1+\frac{26924}{36528+x}=\frac{23}{77}\Leftrightarrow\frac{26924}{36528+x}=-\frac{54}{77}\)