Question

\(\frac{75}{100}-1\frac{1}{2}+0,5:\frac{5}{12}-\left(-\frac{1}{2}\right)^3\)

Answer 1

\(=-\frac{3}{4}+\frac{6}{5}-\left(\frac{-1}{8}\right)\))

=\(-\frac{3}{4}+\frac{6}{5}+\frac{1}{8}\)

=\(\frac{9}{20}+\frac{1}{8}\)

=\(\frac{23}{40}\)

Vậy..........

Answer 2

\(\frac{75}{100}-1\frac{1}{2}+0,5:\frac{5}{12}-\left(-\frac{1}{2}\right)^3\)

= \(\frac{3}{4}-\frac{3}{2}+\frac{6}{5}+\frac{1}{8}\)

= \(\frac{30}{40}-\frac{60}{40}+\frac{48}{40}+\frac{5}{40}\)

= \(\frac{23}{40}\)

Answer 3

\(\frac{75}{100}-1\frac{1}{2}+0,5:\frac{5}{12}-\left(-\frac{1}{2}\right)^3\)

= \(\frac{3}{4}-\frac{3}{2}+\frac{1}{2}:\frac{5}{12}-\frac{-1}{8}\)

= \(\frac{3}{4}-\frac{6}{4}+\frac{1}{2}\cdot\frac{12}{5}-\frac{-1}{8}\)

= \(-\frac{3}{4}+\frac{6}{5}-\frac{-1}{8}=-\frac{30}{40}+\frac{48}{40}-\frac{-6}{40}=\frac{24}{40}=\frac{3}{5}\)

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