\(\frac{7}{4}-y\)x \(\frac{5}{6}=\frac{1}{2}+\frac{1}{3}\)
\(\frac{7}{4}-y\)x \(\frac{5}{6}=\frac{5}{6}\)
\(y\) x \(\frac{5}{6}=\frac{7}{4}-\frac{5}{6}\)
\(y\) x \(\frac{5}{6}=\frac{11}{12}\)
y == \(\frac{11}{12}:\frac{5}{6}\)
y == \(\frac{11}{10}\)
Ta có \(\frac{7}{4}-\frac{5}{6}y=\frac{5}{6}\)
\(\frac{7}{4}=\frac{5}{6}y+\frac{5}{6}\)
\(\frac{7}{4}=\frac{5}{6}\left(y+1\right)\)
\(\frac{7}{4}:\frac{5}{6}=y+1\)
\(\frac{7}{4}\cdot\frac{6}{5}=\frac{21}{10}=y+1\)
\(y=\frac{21}{10}-1=\frac{11}{10}\)
\(\frac{7}{4}\)- y x \(\frac{5}{6}\)=\(\frac{5}{6}\)
y x \(\frac{5}{6}\)=\(\frac{5}{6}\)+ \(\frac{7}{4}\)
y x \(\frac{5}{6}\)=\(\frac{31}{12}\)
y=\(\frac{31}{12}\):\(\frac{5}{6}\)
y=\(\frac{31}{10}\)
\(\frac{7}{4}-y\cdot\frac{5}{6}=\frac{5}{6}\)
\(\frac{7}{4}-y=\frac{5}{6}:\frac{5}{6}\)
\(\frac{7}{4}-y=1\)
\(y=\frac{7}{4}-1\)
\(y=\frac{3}{4}\)
7\(yx\frac{5}{6}=\frac{7}{4}-\frac{5}{6}\)