\(\frac{72-x}{3}=\frac{x-18}{5}\)
\(\Rightarrow5\left(72-x\right)=3\left(x-18\right)\)
\(\Rightarrow360-5x=3x-54\)
\(\Rightarrow-5x-3x=-54-360\)
\(\Rightarrow-8x=-414\)
\(\Rightarrow x=207\)
Tìm x, biết: \(\frac{72-x}{3}=\frac{x-18}{5}\)
Tìm x biết \(\frac{72-x}{3}=\frac{x-18}{5}\)
Tìm x:
\(\frac{72-x}{x-18}=\frac{x}{5}\)
Tìm x,y
\(\frac{-5}{\chi}\)=\(\frac{\gamma}{16}\)=\(\frac{-18}{72}\)
\(\frac{2}{\left(x+1\right)\left(x+3\right)}+\frac{5}{\left(x+3\right)+\left(x+8\right)}+\frac{10}{\left(x+8\right)\left(x+18\right)}+\frac{1}{x+18}=\frac{5}{6}\)
Tìm x;y;z
tim x
a,\(\left(x-20\right)+\left(x-19\right)+\left(x-18\right)+....+200+201=201\)
b, \(\frac{x+1}{1}+\frac{2x+3}{3}+\frac{3x+5}{5}+....+\frac{20x+39}{39}=22+\frac{4}{3}+\frac{6}{5}+...+\frac{40}{39}\)
Timx,y biết:
a,\(|x+2|=|2019x+2020|\)
b,\(\frac{x}{18}=\frac{y}{24}\)và -2x+3y=-72
Tìm x,y thuộc Z:
\(\frac{x}{6}-\frac{1}{y}=\frac{1}{2}\)
Tìm x
a) \(\frac{4x+3}{9}=\frac{4}{3}\)
b)\(\frac{32-x}{3}=\frac{x-18}{5}\)
